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try/except for typing and get only 3 numbers if input is either a or b? if user_input == 'a': try: a = int(input('A:')) b =



 

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Video encyclopedia of pool shots torrent. Video Encyclopedia of Pool Shots (VEPS) (2015) HAPS I .Q: Python Try/Except for typing How can I add try/except for typing and get only 3 numbers if input is either a or b? if user_input == 'a': try: a = int(input('A:')) b = int(input('B:')) c = int(input('C:')) except ValueError: print('Please enter 3 numbers.') else: try: b = int(input('B:')) a = int(input('A:')) c = int(input('C:')) except ValueError: print('Please enter 3 numbers.') A: I think this is a more pythonic way. input_a = input('A:') input_b = input('B:') if input_a == 'a' or input_b == 'b': try: a = int(input_a) b = int(input_b) c = int(input_c) except ValueError: print('Please enter 3 numbers.') else: try: b = int(input_b) a = int(input_a) c = int(input_c) except ValueError: print('Please enter 3 numbers.') I tested this with both input a and input b.




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